Q. The sum of ages of five children born at the intervals of three years each is fifty years. What
is the age of the smallest child?
A. 2
B. 4
C. 8
D. 12
E. None of these
Solution: The correct answer is B.
1st child age = x
2nd child age = (x + 3)
3rd child age = (x + 6)
4th child age = (x + 9)
5th child age = (x + 12)
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Sum of child ages = 50
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Let
the ages of children be x, (x + 3), (x + 6), (x +
9) and (x + 12) years.
Then,
x + (x + 3) + (x + 6) + (x +
9) + (x + 12) = 50
By simplifying, we get
=> 5x + 30 = 50
=> 5x +30 - 30 = 50 -30
=> 5x =20
=> x = 20/5
=> x = 4
Hence, the smallest child age is 4.
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