Q.
In a throw of coin what is probability of getting head ?
A.
1
B.
2
C.
0.5
D.
1.5
E.
None of these
Solution:
Right answer is C =0.5 = ½
Favorable cases = [H] =1
Total cases = [H,T]=2
So, Probability of getting head is = H / [H,T] = ½ = 0.5
Favorable cases = [H] =1
Total cases = [H,T]=2
So, Probability of getting head is = H / [H,T] = ½ = 0.5
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